tmh8286 Posted March 15, 2007 Share Posted March 15, 2007 Pomeroy has got a nice look at the Tournament from a statistical point of view. Here's how he figures our bracket: Here?s the East Region: 2nd Rd Sweet16 Elite8 Final4 Finals Champs 1 N. Carolina 99.26% 81.43% 67.94% 48.69% 32.61% 20.90% 2 Georgetown 96.59% 81.33% 67.30% 32.43% 17.66% 9.09% 4 Texas 88.43% 55.85% 14.54% 6.11% 2.14% 0.69% 9 Mich. St. 60.71% 12.72% 7.24% 3.09% 1.10% 0.36% 3 Wash. St. 81.51% 52.09% 14.57% 3.27% 0.83% 0.19% 12 Arkansas 55.18% 24.33% 4.61% 1.52% 0.40% 0.09% 7 Boston Coll. 64.90% 13.48% 7.16% 1.44% 0.33% 0.07% 8 Marquette 39.29% 5.82% 2.70% 0.91% 0.24% 0.06% 6 Vanderbilt 71.57% 34.34% 7.68% 1.35% 0.27% 0.05% 5 USC 44.82% 17.69% 2.86% 0.83% 0.19% 0.04% 10 Texas Tech 35.10% 4.62% 1.79% 0.22% 0.03% 0.00% 13 New Mex. St. 11.57% 2.13% 0.11% 0.01% 0.00% 0.00% 11 GW 28.43% 8.04% 0.90% 0.08% 0.01% 0.00% 14 Oral Roberts 18.49% 5.52% 0.52% 0.04% 0.00% 0.00% 15 Belmont 3.41% 0.57% 0.09% 0.00% 0.00% 0.00% 16 E. Kentucky 0.74% 0.03% 0.00% 0.00% 0.00% 0.00% He's giving us about a one in five chance of winning today - I'll take that! Quote Link to comment Share on other sites More sharing options...
ORUTerry Posted March 15, 2007 Share Posted March 15, 2007 Not a lot of love for PAC-10 members Washington State (#3) or USC (#5). How about those Hogs? Quote Link to comment Share on other sites More sharing options...
tmh8286 Posted March 15, 2007 Author Share Posted March 15, 2007 Other 14 seeds: 14 Pennsylvania 4.93% 0.72% 0.08% 0.01% 0.00% 0.00% 14 Miami (OH) 13.98% 2.31% 0.21% 0.02% 0.00% 0.00% 14 Wright St. 10.29% 1.22% 0.12% 0.01% 0.00% 0.00% Statistically, we have the best chance of winning the first round of any 14 seed. Quote Link to comment Share on other sites More sharing options...
tmh8286 Posted March 15, 2007 Author Share Posted March 15, 2007 Lots of good tournament info on Ken's blog: Pomeroy Blog Did I ever say how much I love this guy's website??? Quote Link to comment Share on other sites More sharing options...
Bogus Smith Posted March 15, 2007 Share Posted March 15, 2007 Makes me feel like Western Illinois...no chance whatsoever to win the Tournament! Kinda ironic that 17% of #14-seeds have won and Pomeroy has us at 18%. I guess he's playing the odds. Quote Link to comment Share on other sites More sharing options...
tmh8286 Posted March 15, 2007 Author Share Posted March 15, 2007 Not quite that simple, Bogus (as I know you know ). Ken's using log5 analysis to generate those numbers. Here's how it's done: Log5 method From Wiki Gonzalez This is the name Bill James gave for a simple(?) derivation of what is the probability that a given team A with AWin% would beat another team B with BWin%. ProbABeatsB = (AWin% * (1 - BWin%)) / ((AWin% * (1 - BWin%)) + ((1 - AWin%) * BWin%)) = (AWin% - (BWin% * AWin%)) / (AWin% + BWin% - (2 * AWin% * BWin%)) The simple reasoning here is you can imagine AWin and BWin as two independent random variables that get a "win" with AWin% and BWin% respectively and a "loss" with 1 - AWin% and 1 - BWin% respectively. A game in essence is comparing randomly these two random variables and saying A wins only if A picked "win" and B picked "loss" but saying A losses only when A picked "loss" and B picked "win". If A and B picked the same run again. Retrieved from "http://digamma.net/btfwiki/Log5_method" Quote Link to comment Share on other sites More sharing options...
Bogus Smith Posted March 15, 2007 Share Posted March 15, 2007 Not quite that simple, Bogus (as I know you know ). Ken's using log5 analysis to generate those numbers. Here's how it's done: Log5 method From Wiki Gonzalez This is the name Bill James gave for a simple(?) derivation of what is the probability that a given team A with AWin% would beat another team B with BWin%. ProbABeatsB = (AWin% * (1 - BWin%)) / ((AWin% * (1 - BWin%)) + ((1 - AWin%) * BWin%)) = (AWin% - (BWin% * AWin%)) / (AWin% + BWin% - (2 * AWin% * BWin%)) The simple reasoning here is you can imagine AWin and BWin as two independent random variables that get a "win" with AWin% and BWin% respectively and a "loss" with 1 - AWin% and 1 - BWin% respectively. A game in essence is comparing randomly these two random variables and saying A wins only if A picked "win" and B picked "loss" but saying A losses only when A picked "loss" and B picked "win". If A and B picked the same run again. Retrieved from "http://digamma.net/btfwiki/Log5_method" This page has been accessed 749 times. This page was last modified 11:16, 25 Nov 2004. Content is available under GNU Free Documentation License 1.2. TMI Quote Link to comment Share on other sites More sharing options...
Texasgrip Posted March 15, 2007 Share Posted March 15, 2007 Not quite that simple, Bogus (as I know you know ). Ken's using log5 analysis to generate those numbers. Here's how it's done: Log5 method From Wiki Gonzalez This is the name Bill James gave for a simple(?) derivation of what is the probability that a given team A with AWin% would beat another team B with BWin%. ProbABeatsB = (AWin% * (1 - BWin%)) / ((AWin% * (1 - BWin%)) + ((1 - AWin%) * BWin%)) = (AWin% - (BWin% * AWin%)) / (AWin% + BWin% - (2 * AWin% * BWin%)) The simple reasoning here is you can imagine AWin and BWin as two independent random variables that get a "win" with AWin% and BWin% respectively and a "loss" with 1 - AWin% and 1 - BWin% respectively. A game in essence is comparing randomly these two random variables and saying A wins only if A picked "win" and B picked "loss" but saying A losses only when A picked "loss" and B picked "win". If A and B picked the same run again. Retrieved from "http://digamma.net/btfwiki/Log5_method" This page has been accessed 749 times. This page was last modified 11:16, 25 Nov 2004. Content is available under GNU Free Documentation License 1.2. Don't ever post that again... Quote Link to comment Share on other sites More sharing options...
ORUTerry Posted March 15, 2007 Share Posted March 15, 2007 Okay... now I have a headache. Quote Link to comment Share on other sites More sharing options...
ManiacVP Posted March 15, 2007 Share Posted March 15, 2007 I'm in math and society for a reason... and we're having a pi day party today thats right... in honor of yesterday 3/14... we are having a pi day (3.14) party. Dont throw numbers at me when im looking at a good day. Quote Link to comment Share on other sites More sharing options...
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